WAEC 2019 EXPO- PHYSICS ANSWERS


WAEC Physics Specimen 2019

 

Exam Time: Wednesday 8th May, 2019
Physics 2 (Essay) – 09:30 a.m. – 11.00 a.m.
Physics 1 (Objective) – 11:00 a.m. – 12:15 p.m.
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PHYSICS OBJ:
1-10: CBBBCACBCB
11-20: CCCABBBDCD
21-30: CCDADCDDDA
31-40: BDDBBCAABC
41-50:ABDABDBCBA

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(1)
Mass = 20g = (20/100)kg = 0.02kg
Extension = 5cm = (5/100)m = 0.05m
K = 200N/
V = ?
1/2mv² = 1/2ke²
V = √ke²/m = √200×0.05×0.05/0.02
V = √25
V = 5m/s
name

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(2a)

P is initial velocity in m/s

β is angle of projection

H is maximum height

R is Range

 

(2b)

R = P²sin2β/g

at maximum range, sin2β = 1

=> Rmax = p²/g

This happens at β = 45degree

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(3)

(i) magnetic declination

(ii) magnetic inclination

(iii) horizontal components

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(4)

(i) magnetic declination

(ii) magnetic inclination

(iii) horizontal components

 

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(5a)
Free eletcron: These are electrons which are not attached to an atom. They are mobile electrons which are free for bonding.

(5b)
Holes are spaces left by electrons in an atom in a crystal lattice. They are positively charged.

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(6a)
Principle of operation of fiber optics state that the density of transparent glass and the refractive index is greater than the density of the two mirrors. It makes use of the principle of the total internal reflection.

(6b)
(i) It is used to view deep down the throat of a patient
(ii) It is used to conveying information

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(8)
name

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(9ai)

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process.

 

(9aii)

(i)surface area in contact with atmosphere

(ii)nature of the liquid

 

(9bi)

The rate of absorption of heat by clay pot is less than the rate of absorption of heat by plastics. Also, water gets evaporated in a clay pot which the evaporation causes cooling; so water in a clay pot remains cool

 

(9bii)

An increase in pressure in the cooker increase the ambient temperature in the cooker hence the food cooks faster

 

(9c)

(i) Change in the state of a substance

(ii) Increase in temperature

 

(9di)

Heat supplied = m1

lvt = m1

12*40*1400=1.5*1

L=12*40*1400/1.5

L=672000/1.5= 448,000J/kg

Laten heat of fusion of the body = 4.48*10^5J/Kg

 

(9dii)

lvt=mc D tita

12*40*72=1.5*c*60

C=12*40*72/1.5*60

C=384J/Kg/K

Specific heat capacity of the body =384J/Kg/K

name

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(11ai)
Force is anything that causes motion.Its S.I unit is Newton(N) or Kgm/s^2

(11aii)
(i) Static friction
(ii) Dynamic friction

(11bi)
DRAW THE GRAPH

(11bii)
Deceleration
during last 5s=18/5=3.6m/s^2

(11biii)
Total distance=S1+S2+S3+S4
=(30*20)+1/2(18+30)(6)+(18*10)=(1/2*5*18)
=600+144+180+45
=969metres

 

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